6[3-(4+6x)]-2x=-8+2(1-19x)

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Solution for 6[3-(4+6x)]-2x=-8+2(1-19x) equation:


Simplifying
6[3 + -1(4 + 6x)] + -2x = -8 + 2(1 + -19x)
6[3 + (4 * -1 + 6x * -1)] + -2x = -8 + 2(1 + -19x)
6[3 + (-4 + -6x)] + -2x = -8 + 2(1 + -19x)

Combine like terms: 3 + -4 = -1
6[-1 + -6x] + -2x = -8 + 2(1 + -19x)
[-1 * 6 + -6x * 6] + -2x = -8 + 2(1 + -19x)
[-6 + -36x] + -2x = -8 + 2(1 + -19x)

Combine like terms: -36x + -2x = -38x
-6 + -38x = -8 + 2(1 + -19x)
-6 + -38x = -8 + (1 * 2 + -19x * 2)
-6 + -38x = -8 + (2 + -38x)

Combine like terms: -8 + 2 = -6
-6 + -38x = -6 + -38x

Add '6' to each side of the equation.
-6 + 6 + -38x = -6 + 6 + -38x

Combine like terms: -6 + 6 = 0
0 + -38x = -6 + 6 + -38x
-38x = -6 + 6 + -38x

Combine like terms: -6 + 6 = 0
-38x = 0 + -38x
-38x = -38x

Add '38x' to each side of the equation.
-38x + 38x = -38x + 38x

Combine like terms: -38x + 38x = 0
0 = -38x + 38x

Combine like terms: -38x + 38x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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